Solve 18:3 (5-4+1) | Microsoft Math Solver Solve Evaluate View solution steps Factor Quiz Arithmetic 5 problems similar to: Share Examples Quadratic equation Trigonometry Linear equation Arithmetic Matrix Simultaneous equation Differentiation Integration Limits Solve your math problems using our free math solver with step-by-step solutions.
1² = 1. 2² = 4. 3² = 9. 4² = 16. 5² = 25. 16 + 25 = 41. Answer: 4 and 5. Other method: n, n + 1 - two consecutive positive integers. The equation: n² + (n + 1)² = 41 use (a + b)² = a² + 2ab + b². n² + n² + 2(n)(1) + 1² = 41. 2n² + 2n + 1 = 41 subtract 41 from both sides. 2n² + 2n - 40 = 0 divide both sides by 2. n² + n - 20 = 0
x^3+27: 30: Factor: x^2-5x+6: 31: Evaluate: square root of 24: 32: Factor: x^2-36: 33: Factor: x^2-4x+4: 34: Evaluate-4^2: 35: Factor: x^2-x-6: 36: Factor: x^4-81: 37: Factor: x^3-64: 38: Evaluate: 4^3: 39: Factor: x^3-1: 40: Graph: y=x^2: 41: Evaluate: 2^3: 42: Evaluate (-12+ square root of -18)/60: 43: Factor: x^2-6x+9: 44: Factor: x^2-64: 45
Linear equation y = 3x +4 Arithmetic 699 ∗533 Matrix [ 2 5 3 4][ 2 −1 0 1 3 5] Simultaneous equation { 8x + 2y = 46 7x + 3y = 47 Differentiation dxd (x −5)(3x2 −2) Integration ∫ 01 xe−x2dx Limits x→−3lim x2 +2x −3x2 −9 More Examples Pre-Algebra
A is red, B is yellow, C is green, and so on. If you choose only one element r = 1 r = 1 r = 1 at once from that set, the number of combinations will be 12 12 12 - because there are 12 different balls. However, if you choose r = 12 r = 12 r = 12 elements, there'll be only 1 1 1 possible combination that includes every ball. Try it by yourself
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3 4 1 5 answer
